X^2+36x-3600=0

Solution for X^2+36x-3600=0 equation:

X^2+36X-3600=0

a = 1; b = 36; c = -3600;
Δ = b2-4ac
Δ = 362-4·1·(-3600)
Δ = 15696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15696}=\sqrt{144*109}=\sqrt{144}*\sqrt{109}=12\sqrt{109}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12\sqrt{109}}{2*1}=\frac{-36-12\sqrt{109}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12\sqrt{109}}{2*1}=\frac{-36+12\sqrt{109}}{2}
$